integral of ln x over x squared

Evaluate the integral (lnx)/x^9 dx? - Yahoo! Answers.

How do you solve the integral ln x / x dx by substitution? - Yahoo.
integral - Evaluating $int _0 ^1 x^k(ln x)^m dx$ for integer $k$ and.

integral of ln x over x squared

∫ cos[ln(x)] dx : please help integrate, would you? - Yahoo! Answers.
x-2 / x-1 = 1 - (1/(x-1)) Now we have to take the integral of each. The integral of 1 is x and the integral of 1/(x-1) is ln|x-1|. I think. The answer is.
Once you express -1/2(ln|x - 2|/|x - 4|) = -1/2(ln|x -2| - ln|x -4|), you can see that your integral should be something like: integral of:dx/(x -2) +.
May 4, 2006. In order to find the integral of 1/(x*ln(x)) dx, I tried using the substitution. Its an improper integral with lower limit 2 and upper limit infinity.
1/2 (lnx)^2 + c ok, here we go int ( lnx / x dx) = = int ( lnx d lnx ) now think of ln x as a new x, i.e a new variable of integration going in and out of.
v=-1/8x^8 dv=1/x^9 so uv-int vdu (lnx)(-1/8x^8) - int (-1/8x^8)(1/x)dx is this correct so. It looks right, but let me do it over again from scratch. I just caught a. evaluate the integral (4-x^2)^1/2 dx with limits 2 and 0… How do you.

Integral tanh(x) - Math.

(Integral from 1 to infinity) [ln(x)]/[x^2] Convergent or. - OpenStudy.

Karl's Calculus Tutor - 11.4 Integration by Parts.
x-2 / x-1 = 1 - (1/(x-1)) Now we have to take the integral of each. The integral of 1 is x and the integral of 1/(x-1) is ln|x-1|. I think. The answer is.